[ntpwg] ntpwg Updated NTPv4 Protocol Specification/timestamp location
STUART VENTERS
stuart.venters at adtran.com
Thu Feb 7 15:34:35 UTC 2008
Dave,
>>Let t1, t4 belong to A and t2, t3 belong to B. From A's point of view,
>>t2 is late by D and t3 is late by D. Prestatus equationatus.
Yeeeesssss, finally, your words match the example.
I had given up all hope.
Now it appears there is a glimmer of light in the long tunnel.
A consequence of your words appears to be that
the resulting offset eqn calculated at A is:
offset = {[(t2 + D) - t1] + [(t3 + D) - t4]} / 2
for the example, offset = D = -(packet time)
If you agree with this baby step, then let's pop the question stack for the example.
If the 'the delays are still reciprocal' and the client and server clocks are aligned, then shouldn't the offset equation equal zero?
73's,
Stuart
ps, My morse is rusty, I meant to say QRT for I had truly given up.
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