[ntpwg] ntpwg Updated NTPv4 Protocol Specification/timestamp location

David L. Mills mills at udel.edu
Thu Feb 7 17:34:08 UTC 2008


Stuart,

No, compare your equation with mine. The view has to be from A, so the 
delay cancels.

...-.-

Dave

STUART VENTERS wrote:

> Dave,
>
>>> Let t1, t4 belong to A and t2, t3 belong to B. From A's point of view,
>>> t2 is late by D and t3 is late by D. Prestatus equationatus.
>>
>
> Yeeeesssss, finally, your words match the example.
> I had given up all hope.
> Now it appears there is a glimmer of light in the long tunnel.
>
> A consequence of your words appears to be that
> the resulting offset eqn calculated at A is:
> offset = {[(t2 + D) - t1] + [(t3 + D) - t4]} / 2
>
> for the example, offset = D = -(packet time)
>
>
> If you agree with this baby step, then let's pop the question stack 
> for the example.
>
> If the 'the delays are still reciprocal' and the client and server 
> clocks are aligned, then shouldn't the offset equation equal zero?
>
>
> 73's,
>
> Stuart
>
> ps, My morse is rusty, I meant to say QRT for I had truly given up.
>
>



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